320=10x^2

Solution for 320=10x^2 equation:

320=10x^2

We move all terms to the left:

320-(10x^2)=0

a = -10; b = 0; c = +320;
Δ = b2-4ac
Δ = 02-4·(-10)·320
Δ = 12800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12800}=\sqrt{6400*2}=\sqrt{6400}*\sqrt{2}=80\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{2}}{2*-10}=\frac{0-80\sqrt{2}}{-20}
=-\frac{80\sqrt{2}}{-20}
=-\frac{4\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{2}}{2*-10}=\frac{0+80\sqrt{2}}{-20}
=\frac{80\sqrt{2}}{-20}
=\frac{4\sqrt{2}}{-1}
$